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(2^m)=(1/16)
We move all terms to the left:
(2^m)-((1/16))=0
We add all the numbers together, and all the variables
2^m-((+1/16))=0
We multiply all the terms by the denominator
2^m*16))-((+1=0
Wy multiply elements
32m^2+1=0
a = 32; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·32·1
Δ = -128
Delta is less than zero, so there is no solution for the equation
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